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6x^2+42x-360=0
a = 6; b = 42; c = -360;
Δ = b2-4ac
Δ = 422-4·6·(-360)
Δ = 10404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10404}=102$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-102}{2*6}=\frac{-144}{12} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+102}{2*6}=\frac{60}{12} =5 $
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